11d^2-35d+6=0

Solution for 11d^2-35d+6=0 equation:

11d^2-35d+6=0

a = 11; b = -35; c = +6;
Δ = b2-4ac
Δ = -352-4·11·6
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-31}{2*11}=\frac{4}{22}
=2/11
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+31}{2*11}=\frac{66}{22}
=3
$